pindex — Returns the value of a specified pfield.
Here is an example of the pindex opcode. Play pindex.csd
Example 759. Example of the pindex opcode.
See the sections Real-time Audio and Command Line Flags for more information on using command line flags.
<CsoundSynthesizer> <CsOptions> ; Select audio/midi flags here according to platform ; Audio out Audio in No messages MIDI in -odac -iadc ; -d -M0 ;;;RT audio I/O with MIDI in ; For Non-realtime ouput leave only the line below: ;-o pindex.wav -W ;;; for file output any platform </CsOptions> <CsInstruments> ;Example by Anthony Kozar Dec 2006 instr 1 inum pcount index init 1 loop1: ivalue pindex index printf_i "p%d = %f\n", 1, index, ivalue index = index + 1 if (index <= inum) igoto loop1 print inum endin </CsInstruments> <CsScore> i1 0 3 40 50 ; has 5 pfields i1 1 2 80 ; has 5 due to carry i1 2 1 40 50 60 70 ; has 7 e </CsScore> </CsoundSynthesizer>
The example will produce the following output:
new alloc for instr 1:
WARNING: instr 1 uses 3 p-fields but is given 5
p1 = 1.000000
p2 = 0.000000
p3 = 3.000000
p4 = 40.000000
p5 = 50.000000
instr 1: inum = 5.000
B 0.000 .. 1.000 T 1.000 TT 1.000 M: 0.0
new alloc for instr 1:
WARNING: instr 1 uses 3 p-fields but is given 5
p1 = 1.000000
p2 = 1.000000
p3 = 2.000000
p4 = 80.000000
p5 = 50.000000
instr 1: inum = 5.000
B 1.000 .. 2.000 T 2.000 TT 2.000 M: 0.0
new alloc for instr 1:
WARNING: instr 1 uses 3 p-fields but is given 7
p1 = 1.000000
p2 = 2.000000
p3 = 1.000000
p4 = 40.000000
p5 = 50.000000
p6 = 60.000000
p7 = 70.000000
instr 1: inum = 7.000
The warnings can be ignored, because the pfields are used indirectly through pindex instead of explicitly through p4, p5, etc.
Here is another example of the pindex opcode. Play pindex-2.csd
Example 760. Second example of the pindex opcode.
<CsoundSynthesizer> <CsOptions> ; Select audio/midi flags here according to platform -odac ;;;realtime audio ;-iadc ;;;uncomment -iadc if realtime audio input is needed too ; For Non-realtime ouput leave only the line below: ; -o pindex-2.wav -W ;;; for file output any platform </CsOptions> <CsInstruments> sr = 44100 ksmps = 32 nchnls = 2 0dbfs = 1 ; This UDO returns a pfield value but returns 0 if it does not exist. opcode mypvalue, i, i index xin inum pcount if (index > inum) then iout = 0.0 else iout pindex index endif xout iout endop ; Envelope UDO that reads parameters from a flexible number of pfields ; Syntax: kenv flexlinseg ipstart ; ipstart is the first pfield of the envelope ; parameters. Reads remaining pfields (up to 21 of them). ; kenv is the output envelope. opcode flexlinseg, k, i ipstart xin iep1 mypvalue ipstart iep2 mypvalue ipstart + 1 iep3 mypvalue ipstart + 2 iep4 mypvalue ipstart + 3 iep5 mypvalue ipstart + 4 iep6 mypvalue ipstart + 5 iep7 mypvalue ipstart + 6 iep8 mypvalue ipstart + 7 iep9 mypvalue ipstart + 8 iepa mypvalue ipstart + 9 iepb mypvalue ipstart + 10 iepc mypvalue ipstart + 11 iepd mypvalue ipstart + 12 iepe mypvalue ipstart + 13 iepf mypvalue ipstart + 14 iepg mypvalue ipstart + 15 ieph mypvalue ipstart + 16 iepi mypvalue ipstart + 17 iepj mypvalue ipstart + 18 iepk mypvalue ipstart + 19 iepl mypvalue ipstart + 20 kenv linseg iep1, iep2, iep3, iep4, iep5, iep6, iep7, iep8, \ iep9, iepa, iepb, iepc, iepd, iepe, iepf, iepg, \ ieph, iepi, iepj, iepk, iepl xout kenv endop instr 1 ; This instrument only requires 3 pfields but can accept up to 24. ; (You will still get warnings about more than 3). kenv flexlinseg 4 ; envelope params start at p4 aout oscili kenv*.5, 256, 1 outs aout, aout endin </CsInstruments> <CsScore> f1 0 8192 10 1 i1 0 2 0.0 1.0 1.0 1.0 0.0 i1 2 2 0.0 0.1 1.0 1.0 1.0 0.1 0.0 i1 4 2 0.0 0.5 0.0 ; one problem is that "missing" pfields carry i1 6 2 0.0 0.5 0.0 ! ; now we can fix this problem with ! i1 8 10 0.0 3.0 1.0 0.3 0.1 0.3 1.0 0.3 0.1 0.3 1.0 0.3 0.1 0.8 0.9 5.0 0.0 e </CsScore> </CsoundSynthesizer>
The example will produce the following output:
WARNING: instr 1 uses 3 p-fields but is given 8
B 0.000 .. 2.000 T 2.000 TT 2.000 M: 0.49966 0.49966
WARNING: instr 1 uses 3 p-fields but is given 10
B 2.000 .. 4.000 T 4.000 TT 4.000 M: 0.50000 0.50000
WARNING: instr 1 uses 3 p-fields but is given 10
B 4.000 .. 6.000 T 6.000 TT 6.000 M: 0.49943 0.49943
WARNING: instr 1 uses 3 p-fields but is given 6
B 6.000 .. 8.000 T 8.000 TT 8.000 M: 0.00000 0.00000
WARNING: instr 1 uses 3 p-fields but is given 20
B 8.000 .. 18.000 T 18.000 TT 18.000 M: 0.49994 0.49994